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Using hook_form_alter(), you can change any form. All you need to know is the form s ID. There are two approaches to altering forms.

GetHashCode()

ToString()

function formexample_form_alter(&$form, &$form_state, $form_id) { // This code gets called for every form Drupal builds; use an if statement // to respond only to the user login block and user login forms. if ($form_id == 'user_login_block' || $form_id == 'user_login') { // Add a dire warning to the top of the login form. $form['warning'] = array( '#markup' => t('We log all login attempts!'), '#weight' => -5 ); // Change 'Log in' to 'Sign in'. $form['submit']['#value'] = t('Sign in'); } } Since $form is passed by reference, we have complete access to the form definition here and can make any changes we want. In the example, we added some text using the default form element (see Markup later in this chapter) and then reached in and changed the value of the Submit button.

GetType()

MemberwiseClone()

The previous approach works, but if lots of modules are altering forms and every form is passed to every hook_form_alter() implementation, alarm bells may be going off in your head. This is wasteful, you re probably thinking. Why not just construct a function from the form ID and call that You are on the right track. Drupal does exactly that. So the following function will change the user login form too: function formexample_form_user_login_alter(&$form, &$form_state) { $form['warning'] = array( '#value' => t('We log all login attempts!'), '#weight' => -5 ); // Change 'Log in' to 'Sign in'. $form['submit']['#value'] = t('Sign in'); The function name is constructed from this: modulename + 'form' + form ID + 'alter' For example, 'formexample' + 'form' + 'user_login' + 'alter' results in the following: formexample_form_user_login_alter In this particular case, the first form of hook_form_alter() is preferred, because two form IDs are involved (user_login for the form at http://example.com/ q=user and user_login_block for the form that appears in the user block).

To illustrate some of the default behavior provided by the Object base class, create a new C# Console Application named ObjectOverrides. Insert a new C# class type that contains the following empty class definition for a type named Person: // Remember! Person extends Object. class Person {} Now, update your Main() method to interact with the inherited members of System.Object as follows: class Program { static void Main(string[] args) { Console.WriteLine("***** Fun with System.Object *****\n"); Person p1 = new Person(); // Use inherited members of System.Object. Console.WriteLine("ToString: {0}", p1.ToString()); Console.WriteLine("Hash code: {0}", p1.GetHashCode()); Console.WriteLine("Type: {0}", p1.GetType());

// Make some other references to p1 Person p2 = p1; object o = p2; // Are the references pointing to the same object in memory if (oEquals(p1) && p2Equals(o)) { ConsoleWriteLine("Same instance!"); } ConsoleReadLine(); } } Here is the output of the current Main() method ***** Fun with SystemObject ***** ToString: ObjectOverridesPerson Hash code: 46104728 Type: ObjectOverridesPerson Same instance! First, notice how the default implementation of ToString() returns the fully qualified name of the current type (ObjectOverridesPerson) As you will see later during the examination of building custom namespaces in 14, every C# project defines a root namespace, which has the same name of the project itself Here, you created a project named ObjectOverrides; thus the Person type (as well as the Program class) have both been placed within the ObjectOverrides namespace.